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How do you find the distance between two vehicles when they are about to past each other?

The distance form Redding to Bishop is 400 miles. A motorcycle leaves Redding riding to Bishop at 70 mph. Then 40 minutes later an SUV leaves Bishop for Redding at 75 mph. How far from Redding will the two vehicles be when they pass? PLEAASE HELP! IM SO CONFUSED!

Public Comments

1. note: Xr = the distance from Redding to meeting point. Vm = the speed of the motorcycle (70m/h) Vs = the speed of the SUV (75m/h) T = the time in which the motorcycle arrive at the meeting point 400 Miles - Xd = The distance from Bishop to meeting point. we need 2 equations with 2 unknowns (Xd and T) we write the motion equations for the tho vehicles Xd =Vm * T 400M - Xd=Vs*(T -40 minutes) so ((40 min=2/3 Hours)) Xd =Vm * T 400M - Xd=Vs*T - Vs*2/3 Hours so ((we replace the speeds) Xd=70m/h*T 400m -Xd=75m/h*T - 75m/h*2/3h so ((75m/h*2/3h = 50m)) Xd=70m/h*T 400m -Xd=75m/h*T - 50m so ((we multiply the second equation by -1 )) Xd=70m/h*T -400m + Xd = -75m/h*T + 50m so ((we multiplay the first equation by 75/70 )) 75/70 * Xd = 75m/h * T -400m + Xd = -75m/h*T + 50m so ((we add the 2 equations, term by term)) 75/70 *Xd -400m +Xd = 50m so 75/70*Xd + Xd = 50m + 400m so Xd* (75/70 + 1 ) = 450m so (( 1=70/70 )) Xd*(75/70 +70/70) =450m so Xd* 145/70= 450m so Xd= 450m *70/145 so Xd = 217,24 miles Hope that helps !!